SOLUTION: If a population proportion is 0.32 and if the sample size is 100, 45% of the time the sample proportion will be more than what value if you are taking random samples?
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Question 1189929: If a population proportion is 0.32 and if the sample size is 100, 45% of the time the sample proportion will be more than what value if you are taking random samples? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! The standard error is sqrt(p*(1-p)/n)=sqrt(0.32*0.68/100)=0.0466
45% of the time greater occurs with a z=+0.1257
z*SE is margin of error or in this instance the value where 45% are more than the mean of 32 with a sample size of 100. It is 0.0059
so the proportion is 0.326 and for 100, that would be a mean of 32.6
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can check by approximation
mean is np=32
variance is np(1-p)=32*0.68=21.76
sd is sqrt (V)=4.66
0.1257 of that sd is 0.59, and add that to the mean and get 32.6
