Question 1189925: The Royal Fruit Company produces two types of fruit drinks. The first type is 20% pure fruit juice, and the second type is 70% pure fruit juice. The company is attempting to produce a fruit drink that contains 60% pure fruit juice. How many pints of each of the two existing types of drink must be used to make 120 pints of a mixture that is 60% pure fruit juice?
Found 3 solutions by mananth, josgarithmetic, greenestamps:
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website!
20% pure fruit juice,let quantity be x pints
and the second type; 70% pure fruit juice (120-x) pints
Mixture 120 pints 60%
20%x +70%(120-x) =60% * 120
Multiply by 100
20x+70(120-x) =60*120
OR
2x+7(120-x)= 6*120
2x +840 -7x = 720
5x =120
x = 24 pints
Answer by josgarithmetic(39630)  (Show Source):
You can put this solution on YOUR website! The Royal Fruit Company, again, the same two-part mix problem but using different given values.
PERCENT JUICE VOLUME, pints PURE JUICE
firsttype 20 120-v 20(120-v)
secondtype 70 v 70v
results 60 120 (60)(120)
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Answer by greenestamps(13209)  (Show Source):
You can put this solution on YOUR website!
A quick and easy way to solve any 2-part mixture problem like this, if the numbers are "nice", and if a formal algebraic solution is not required.
(1) Look at the three percentages 20, 60, and 70 (on a number line, if it helps) and observe/calculate that 60 is 40/50=4/5 of the way from 20 to 70.
(2) That means 4/5 of the mixture is the 70% fruit juice.
ANSWER: 4/5 of 120 pints, or 96 pints, of the 70% fruit juice; the other 24 pints of the 20% fruit juice.
CHECK: .70(96)+.20(24)=67.2+4.8=72
.60(120)=72
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