SOLUTION: A chef is going to use a mixture of two brands of Italian dressing. The first brand contains 8% vinegar, and the second brand contains 13% vinegar. The chef wants to make 370 milli
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Question 1189875: A chef is going to use a mixture of two brands of Italian dressing. The first brand contains 8% vinegar, and the second brand contains 13% vinegar. The chef wants to make 370 milliliters of a dressing that is 12% vinegar. How much of each brand should she use? Answer by ikleyn(52754) (Show Source):
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A chef is going to use a mixture of two brands of Italian dressing.
The first brand contains 8% vinegar, and the second brand contains 13% vinegar.
The chef wants to make 370 milliliters of a dressing that is 12% vinegar.
How much of each brand should she use?
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In this problem, concentrations are the ratios of the pure vinegar volume to the total volume.
Let x be the amount of the 8% vinegar needed (in milliliters), and
let y be the amount of the 13% vinegar needed.
The amount of the "pure" vinegar in the 8% mixture is 0.08x mL.
The amount of the "pure" vinegar in the 13% mixture is 0.13y mL.
The resulting mixture contains 0.08x + 0.13y mL of the pure vinegar and has the volume of 370 mL.
Thus you have these two equations
x + y = 370 milliliters (1) (the total volume)
= 0.12. (2) (the resulting mixture concentration)
From equation (1), express x = 370 - y. Substitute it into equation (2) and multiply both sides of this equation by 370.
You will get
0.08*(370-y) + 0.13y = 0.12*370.
From the last equation express y and calculate
y = = 296 mL of the 13% vinegar are needed.
Then from equation (1), x = 370 - 296 = 74 mL of the 8% vinegar are needed.
Answer. 296 mL of the 13% vinegar and 74 mL of the 8% vinegar are needed.
Check. = 0.12 = 12%. ! Correct concentration !