| 
 
 
 
Question 1189865:  A certain brand of house paint must be purchased either in quarts at $12 each or in gallons at $18 each. A painter needs a 3-gallon mixture of the paint consisting of 3 parts blue and 2 parts white. What is the least amount of money needed to purchase sufficient quantities of the two colors to make the mixture? 
a)$54  b)$60  c)$66  d)$90  e)$144 
 Found 2 solutions by  ikleyn, ankor@dixie-net.com: Answer by ikleyn(52903)      (Show Source): 
You can  put this solution on YOUR website! . 
A certain brand of house paint must be purchased either in quarts at $12 each or in gallons at $18 each.  
A painter needs a 3-gallon mixture of the paint consisting of 3 parts blue and 2 parts white.  
What is the least amount of money needed to purchase sufficient quantities of the two colors  
to make the mixture? 
a)$54 b)$60 c)$66 d)$90 e)$144 
~~~~~~~~~~~~~~
 
 
 
            This problem is to apply common sense and a bit of arithmetic and simple algebra.
 
 
 
To start, notice that
    1 gallon = 4 quarts,  and
    buying in gallons is much cheaper than buying the same amount in quarts, both for blue and for white paint.
The parts of the 3-gallon mixture are 1.8 gallons of blue paint and 1.2 gallons of white paint 
    (easy calculate with algebra  3x + 2x = 3 gallons;  5x = 3 gallons;  x = 0.6 of a gallon;  and the parts are 3x and 2x).
    +---------------------------------------------------------------------------------+
    |        So, we can solve the problem (minimize the cost) separately              |
    |    for 1.8 gallons of the blue paint and for 1.2 gallons of the white paint.    |
    +---------------------------------------------------------------------------------+
1.8 gallons of the blue paint is the same as 1 gallon and 3.2 quarts,
so for 1.8 gallons of the blue paint we have two options:
    to buy 1 gallon plus 4 quarts separately,  which costs  18 + 4*12 = 66 dollars,
    or to buy 2 gallons (which is enough),  which costs  2*18 = 36 dollars.
The choice is clear, and we buy 2 gallons of the blue paint, paying 36 dollars.
1.2 gallons of the white paint is the same as 1 gallon and 0.8 quarts,
so for 1.2 gallons of the white paint we have two options:
    to buy 1 gallon plus 1 quarts,  which costs  18 + 12 = 30 dollars,
    or to buy 2 gallons (which is enough),  which costs  2*18 = 36 dollars.
The choice is clear, and we buy 1 gallon plus 1 quart of the white paint, paying 30 dollars.
In total, the optimal purchase costs  36 + 30 = 66 dollars.     ANSWER
 
Solved.
 
 
 
 
 Answer by ankor@dixie-net.com(22740)      (Show Source): 
You can  put this solution on YOUR website!  A certain brand of house paint must be purchased either in quarts at $12 each or in gallons at $18 each. 
 A painter needs a 3-gallon mixture of the paint consisting of 3 parts blue and 2 parts white. 
 What is the least amount of money needed to purchase sufficient quantities of the two colors to make the mixture? 
: 
3 gal = 12 qts 
let b = amt of blue paint in quarts 
let w = amt of white 
: 
b + w = 12 
and using the ratio of blue to white 
  =   
2b = 3w 
b = (3w)/2 
b = 1.5w 
find in terms of w 
1.5w + w = 12 
2.5w = 12 
w = 12/2.5 
w = 4.8 quarts of white required 
then 
b = 12 - 4.8 = 7.2 quarts of blue 
subtract no. of whole gallons from each, cost 2 *18 = $36  
.8qts of white and 3.2 qts of blue close enough to 4, get another gal of blue 
that would now be 3 * 18 = $54 plus 1 qt of white, 54 + 12 = $66 
:  
Summarize $66: 2 gal of blue ($36), 1 gal and 1 qt of white, ($18 + $12) 
  | 
 
  
 
 |   
 
 |   
 |  |