SOLUTION: The derivative of f(x)=1/sqrt(2x-3), with x>3/2 is

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Question 1189661: The derivative of f(x)=1/sqrt(2x-3), with x>3/2 is
Found 2 solutions by MathLover1, Solver92311:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
The derivative of
f%28x%29=1%2Fsqrt%282x-3%29+
is
%28d%2Fdx%29%281%2Fsqrt%282x-3%29+%29

=%28d%2Fdx%29%28sqrt%282x-3%29+%5E%28-1%2F2%29%29........apply chain rule

=-%281%2F%282%282x-3%29%5E%283%2F2%29%29%29%28d%2Fdx%29%282x-3%29.........%28d%2Fdx%29%282x-3%29=2

=-2%2F%282%282x-3%29%5E%283%2F2%29%29

=-1%2F%282x-3%29%5E%283%2F2%29

f'%28x%29=-1%2F%28%282x-3%29%5E%283%2F2%29%29

domain: { x element R : x%3E3%2F2 }



Answer by Solver92311(821) About Me  (Show Source):
You can put this solution on YOUR website!



is continuous only on the interval so the derivative is defined only on that interval.

Use the chain rule:





John

My calculator said it, I believe it, that settles it


I > Ø