SOLUTION: Find an equation of the tangent line to the graph of the function at the given point: 1+ ln 7xy = e^7x-y, (1/7,1)

Algebra ->  Test -> SOLUTION: Find an equation of the tangent line to the graph of the function at the given point: 1+ ln 7xy = e^7x-y, (1/7,1)      Log On


   

Question 1189591: Find an equation of the tangent line to the graph of the function at the given point:
1+ ln 7xy = e^7x-y, (1/7,1)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find an equation of the tangent line to the graph of the function at the given point:
1+ ln 7xy = e^7x-y, (1/7,1)
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Is it e%5E7%2Ax-y ?
Or e%5E%287x%29+-+y ?