SOLUTION: a canoeist paddled for 4 hrs with a 6km/h current to reach a campsite.the return trip against the same current took 10 hrs.find the speed of the canoe in still water.
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Question 118931: a canoeist paddled for 4 hrs with a 6km/h current to reach a campsite.the return trip against the same current took 10 hrs.find the speed of the canoe in still water. Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! DISTANCE=RATE*TIME
GOING WE HAVE D=4(S+6) WHERE S=SPEED OF THE CANOEIST.
RETURNING WE HAVE D=10(S-6)
SETTING THESE 2 EQUATIONS EQUAL WE GET:
4(S+6)=10(S-6)
4S+24=10S-60
4X-10S=-60-24
-6S=-84
S=-84/-6
S=14 KMH IS THE CANOEIST SPEED.
PROOF
4(14+6)=10(14-6)
4*20=10*8
80=80
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