SOLUTION: https://docs.google.com/document/d/1F8XKL3Lw7pb2tatTq5xHkbXEclumn-b3lRTjzp2QXMQ/edit?usp=sharing How could I solve this quickly, without having to plug each midpoint interval so

Algebra ->  Probability-and-statistics -> SOLUTION: https://docs.google.com/document/d/1F8XKL3Lw7pb2tatTq5xHkbXEclumn-b3lRTjzp2QXMQ/edit?usp=sharing How could I solve this quickly, without having to plug each midpoint interval so      Log On


   



Question 1189188: https://docs.google.com/document/d/1F8XKL3Lw7pb2tatTq5xHkbXEclumn-b3lRTjzp2QXMQ/edit?usp=sharing
How could I solve this quickly, without having to plug each midpoint interval so many times?

Found 2 solutions by ikleyn, Solver92311:
Answer by ikleyn(53937) About Me  (Show Source):
You can put this solution on YOUR website!
.

Frequency distribution table shows how many times n%5Bi%5D would you expect 
appearing of some value x%5Bi%5D of discrete random variable X through the N experiments. 


Frequency distribution table has two arrays: x%5Bi%5D  and n%5Bi%5D.
 

To find the mean  " m ",  use the formula  m = %281%2FN%29%2Asum%28x%5Bi%5D%2An%5Bi%5D%2C+i=1%2CN%29. 


To find the standard deviation " d ",  use the formula  d = sqrt%28%28sum%28n%5Bi%5D%2A%28x%5Bi%5D-m%29%5E2%2Ci=1%2CN%29%29%2FN%29.
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As a reference,  see this link

http://sceo.archives.math.ca/edu/power-pouvoir/ch12/5214891-eng.htm



For an appropriate ONLINE standard deviation calculator for data given as a frequency table,  see the link

https://www.hackmath.net/en/calculator/standard-deviation



Answer by Solver92311(821) About Me  (Show Source):
You can put this solution on YOUR website!


is the number of workers in the interval. is the number of intervals. is the midpoint of the interval. is the mean of the data.



Make columns in your table for , , and , and do the calculations for each interval and then take the appropriate sums.

Then make a column for and calculate each. Then make a column for and calculate each Then make a column for , calculate each, and then sum the column.

Then

And finally, the standard deviation is:




John

My calculator said it, I believe it, that settles it

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