SOLUTION: Simplify and state the values of the variables where the expressions are undefined. [3c / (c^2-25)] x [(c-5) / (6c^2-3c)] / [2 / (c+5)]

Algebra ->  Real-numbers -> SOLUTION: Simplify and state the values of the variables where the expressions are undefined. [3c / (c^2-25)] x [(c-5) / (6c^2-3c)] / [2 / (c+5)]      Log On


   

Question 1189170: Simplify and state the values of the variables where the expressions are undefined.
[3c / (c^2-25)] x [(c-5) / (6c^2-3c)] / [2 / (c+5)]
Found 3 solutions by MathLover1, ankor@dixie-net.com, greenestamps:
Answer by MathLover1(20850) About Me  (Show Source):
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Assuming it is:

right away we can see that it is undefined if c = -5, we get division by 0 in two of the fractions
rewrite this to

simplify

Cancel c-5, c+5 and 3c
1+%2A+%281%2F%282c%2B1%29%29+%2A+%281%2F2%29 = 1%2F2%282c%2B1%29
c = -.5 also makes it undefined

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The expression is undefined wherever the denominator of any fraction is zero, BEFORE simplifying. The given expression is

%28%283c%2F%28c%5E2-25%29%29%28%28c-5%29%2F%286c%5E2-3c%29%29%29%2F%282%2F%28c%2B5%29%29

Factor each denominator....



Oberve that the values of c that make any of the denominators equal to 0 are -5, 5, 0, and 1/2.

To simplify, cancel the common factors 3, c, and (c-5) in the numerator of the complex fraction...

%281%2F%28%28c%2B5%29%282c-1%29%29%29%2F%282%2F%28c%2B5%29%29

... then "flip and multiply":



ANSWER: %28%283c%2F%28c%5E2-25%29%29%28%28c-5%29%2F%286c%5E2-3c%29%29%29%2F%282%2F%28c%2B5%29%29 = 1%2F%284c-2%29; c not equal to -5, 5, 0, or 1/2