SOLUTION: If a sphere of radius 8m rests in a circular hole of radius 3m. How far below the plane of the hole does the sphere extend?

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Question 1189065: If a sphere of radius 8m rests in a circular hole of radius 3m. How far below the plane of the hole does the sphere extend?
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) About Me  (Show Source):
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If a sphere of radius 8m rests in a circular hole of radius 3m. How far below the plane of the hole does the sphere extend?
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It's a right triangle.
Hyp = 8
One side = 3
2nd side = sqrt(8^2 - 3^2) = sqrt(55)
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Below the plane = 8+-+sqrt%2855%29

Answer by ikleyn(52879) About Me  (Show Source):
You can put this solution on YOUR website!
.
If a sphere of radius 8 m rests in a circular hole of radius 3 m.
How far below the plane of the hole does the sphere extend?
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Make a sketch and find a right-angled triangle in it.


The hypotenuse is 8 meters (the radius of the sphere).


One leg is the radius of the small circle, i.e. 3 meters.


Hence, the other leg is  sqrt%288%5E2+-+3%5E2%29 = sqrt%2855%29 = 7.416  meters (rounded).


Thus the value under the problem's question is this difference  8 - 7.416 = 0.584 meters = 58.4 cm = 584 mm.    ANSWER

Solved.