SOLUTION: Find the volume of the solid formed when a circular sector of radius 6 cm and angle of 30° is revolved about its angle bisector.

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Question 1189052: Find the volume of the solid formed when a circular sector of radius 6 cm and angle of 30° is revolved about its angle bisector.
Answer by Alan3354(69443) About Me  (Show Source):
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Find the volume of the solid formed when a circular sector of radius 6 cm and angle of 30° is revolved about its angle bisector.
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Find the height of the spherical segment:
h = 6 - 6*cos(15) =~ 0.204445
Vol+=+2pi%2Ar%5E2h%2F3
Vol =~ 15.41479 cc
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cos%2815%29+=+%28sqrt%286%29+%2B+sqrt%282%29%29%2F4 if you want an exact solution.
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You can split it into a cone and a spherical segment and do it that way, but it's more work.