SOLUTION: In a random sample 72 people 36 are classified as successful
Determine the sample proportion p pf successful people
if the population proportion is 0.70 determine the standard e
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-> SOLUTION: In a random sample 72 people 36 are classified as successful
Determine the sample proportion p pf successful people
if the population proportion is 0.70 determine the standard e
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Question 1188887: In a random sample 72 people 36 are classified as successful
Determine the sample proportion p pf successful people
if the population proportion is 0.70 determine the standard error
the standard error of the sample is equal to the square root of (the the sample p * the sample q divided by the sample size)
that is equal to sqrt(.5 * .5 / 72) = .0589255651.
the z-score formula is:
z = (x - m) / s
x is the z-score
x is the sample mean
m is the population mean
s is the standard error.
the formula becomes:
z = (.5 - .7) / .0589255651 = -3.39411255.
the p-value of the test is the area under the normal distribution curve to the left of a z-score of -3.39411255.
that is equal to 3.443089255 * 10 ^ -4.
the standard value for that is .0003443089255.
that can be rounded to .0003.
the critical p-value is usually .05 or .025 or .01 or .005.
since the p-value of the test is less than the most critical p-value, the results are considered significant, even under the stricter requirement of .005.
in practice, the critical p-value is selected before making the test.
her's a reference on how to calculate the standard error of a sample proportion.
