SOLUTION: solve for x: log base 4(x^2+3x)=1+log base 4(x=5)
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Question 118887
:
solve for x:
log base 4(x^2+3x)=1+log base 4(x=5)
Answer by
solver91311(24713)
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Step 1: Add
to both sides
Step 2: Apply
Step 3: Apply the
=>
equivalency
Step 4: Multiply both sides by (x + 5)
Step 5: Collect terms and put in standard form
Step 6: Factor
or
Check:
but since
,
so
, so
checks
but since
,
so
, so
checks