SOLUTION: You choose a tile at random from a bag containing 2 A's, 3 B's, and 4 C's. You replace the first tile in the bag and then choose again. Find the probability.
P(A and A)
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-> SOLUTION: You choose a tile at random from a bag containing 2 A's, 3 B's, and 4 C's. You replace the first tile in the bag and then choose again. Find the probability.
P(A and A)
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Question 1188653: You choose a tile at random from a bag containing 2 A's, 3 B's, and 4 C's. You replace the first tile in the bag and then choose again. Find the probability.
The total number of tiles is A + B + C = 2 + 3 + 4 = 9.
When you draw first tile and then replace it, you return everything to the original state. THEREFORE
P(A and A) = = .
P(A and B) = = .
P(C and C) = = .
P(B and C) = = .
P(B and B) = = .
