SOLUTION: A chord 18 inches long is perpendicular to the radius of a circle. The distance of the intersection of the chord and the radius to the center of the circle is 3 inches. What is the
Algebra ->
Angles
-> SOLUTION: A chord 18 inches long is perpendicular to the radius of a circle. The distance of the intersection of the chord and the radius to the center of the circle is 3 inches. What is the
Log On
Question 1188600: A chord 18 inches long is perpendicular to the radius of a circle. The distance of the intersection of the chord and the radius to the center of the circle is 3 inches. What is the radius of the circle? illustrate the circle and show your complete solution. Answer by greenestamps(13200) (Show Source):
The radius that is perpendicular to the chord bisects the chord. So the portion of that radius from the center to the chord, half of the chord, and a radius to the end of the chord form a right triangle; the lengths of the legs are 3 (given) and 9 (half of the chord length), and the hypotenuse is the radius of the circle.
Use the Pythagorean Theorem to answer the question.
