SOLUTION: Calculate: A) Tan^2 225degrees-sin 60 degrees cos 30 degrees ( don't understand what the Tan to the exponent 2 means) B) cos 45 degrees sin 225 degrees+ cos 330 degrees

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Question 1188581: Calculate:
A) Tan^2 225degrees-sin 60 degrees cos 30 degrees ( don't understand what the Tan to the exponent 2 means)

B) cos 45 degrees sin 225 degrees+ cos 330 degrees

Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Calculate:
A) Tan^2 225degrees-sin 60 degrees cos 30 degrees ( don't understand what the Tan to the exponent 2 means)
----
It's the tan(225) squared
tan(225) = 1 ---> tan^2(225) = 1
-------
Use parentheses
A) Tan^2(225)-sin(60)*cos(30) = 1+-+%28sqrt%283%29%2F2%29%2A%28sqrt%283%29%2F2%29
= 1 - 3/4 = 1/4
=======================
B) cos(45)*sin(225)+cos(330 = cos(45)*(-sin(45)) + cos(30)

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

tan(225°) = 1

tan^2(225°) = 1^2 = 1

sin(60°) = sqrt%283%29%2F2

cos(30°) = sqrt%283%29%2F2.


Having these my hints, you do the rest.



The angles 0°, 30°, 45°, 60°, 90°, 120°, 135°, 150°, 180°, 210°, 225°, 240°, 270°, 300°, 315°, 330°, 360°

are special angles, and EVERY student studying Trigonometry MUST know the values of all trigonometry functions at these angles

precisely in the same way as more young students know the multiplication table.


If you do not know it,  it means that  YOU  ARE  in  WRONG  CLASS.


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You can find these tables in the  Internet,  see the links


https://www.mathwords.com/t/trig_values_of_special_angles.htm

https://mathvox.com/table-of-the-trig-functions-of-special-angles/

https://www.livingston.org/cms/lib9/NJ01000562/Centricity/Domain/742/calc/Trig%20functions%20chart%20-%20answers.pdf


especially the last link.