SOLUTION: Mr.Ulep has a rectangular field with a length twice its width.If 4 feet are taken from the length and 3 feet are taken from the width, the area of the field is 150 square feet.Find

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Question 1188579: Mr.Ulep has a rectangular field with a length twice its width.If 4 feet are taken from the length and 3 feet are taken from the width, the area of the field is 150 square feet.Find the area of the original field
Found 2 solutions by josgarithmetic, MathLover1:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Dimensions original rectangular field, 2w and w.

The changed dimensions,
%282w-4%29%28w-3%29=150
You should be able to decide what to do.

original length, 22.35
original width, 11.17

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

a rectangular field with a length L twice its width W
L=2W......eq.1
If 4 feet are taken from the length and 3 feet are taken from the width, the area of the field is 150 square feet
%28L-4%29%28W-3%29=150...........eq.2, substitute L
%282W-4%29%28W-3%29=150
2W%5E2+-+10W+%2B+12=150
2W%5E2+-+10W+%2B+12-150=0
2W%5E2+-+10W+-138=0.........divide by 2
W%5E2+-+5W+-69=0
W%5E2+-+5W+-69=0
using quadratic formula we get:
W+=+5%2F2+%2B+sqrt%28301%29%2F2=11.18+
or
W+=+5%2F2+-+sqrt%28301%29%2F2=-6.1746757-> disregard negative solution

L=2%2A11.18=22.36
the area of the original field is:
A=L%2AW
A=22.36%2A11.18
A=249.99
rounded
A=250