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Find the product(xy) if  and
 and 
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Let   = p.     (1)
Then first equation takes the form
    p^2 + p - 20 = 0,  or, factoring,  (p+5)*(p-4) = 0.     (2)
Its roots are p= -5 and p= 4.
Due to definition of p  (1), we suppose, by default, that "p" is positive; so we choose p= 4.
Hence,  x + y = 4^2 = 16.     (3)
Let
 = p.     (1)
Then first equation takes the form
    p^2 + p - 20 = 0,  or, factoring,  (p+5)*(p-4) = 0.     (2)
Its roots are p= -5 and p= 4.
Due to definition of p  (1), we suppose, by default, that "p" is positive; so we choose p= 4.
Hence,  x + y = 4^2 = 16.     (3)
Let   = q.     (4)
Then second equation takes the form
    q^2 + q - 12 = 0,  or, factoring,  (q+4)*(q-3) = 0.     (5)
Its roots are q= -4 and q= 3.
Due to definition of q  (4), we suppose, by default, that "q" is positive; so we choose q= 3.
Hence,  x - y = 3^2 = 9.     (6)
Thus we have these two equations
    x + y = 16     (3)
    x - y =  9     (6)
Solving by elimination, we get  x =
 = q.     (4)
Then second equation takes the form
    q^2 + q - 12 = 0,  or, factoring,  (q+4)*(q-3) = 0.     (5)
Its roots are q= -4 and q= 3.
Due to definition of q  (4), we suppose, by default, that "q" is positive; so we choose q= 3.
Hence,  x - y = 3^2 = 9.     (6)
Thus we have these two equations
    x + y = 16     (3)
    x - y =  9     (6)
Solving by elimination, we get  x =  =
 =  = 12.5;  y = 16-x = 16-12.5 = 3.5.
THEREFORE,  x*y = 12.5*3.5 = 43.75.      ANSWER
 = 12.5;  y = 16-x = 16-12.5 = 3.5.
THEREFORE,  x*y = 12.5*3.5 = 43.75.      ANSWER
Solved.