SOLUTION: The joint probability mass function of X and Y is given by p(1,1)=0.05 p(2,1)=0.1 p(3,1)=0.1 p(1,2)=0.1 p(2,2)=0.25 p(3,2)=0.1 p(1,3)=0.1 p(2,3)=0.1 p(3,3)=0.1 Compute the

Algebra ->  Probability-and-statistics -> SOLUTION: The joint probability mass function of X and Y is given by p(1,1)=0.05 p(2,1)=0.1 p(3,1)=0.1 p(1,2)=0.1 p(2,2)=0.25 p(3,2)=0.1 p(1,3)=0.1 p(2,3)=0.1 p(3,3)=0.1 Compute the       Log On


   

Question 1188500: The joint probability mass function of X and Y is given by
p(1,1)=0.05 p(2,1)=0.1 p(3,1)=0.1
p(1,2)=0.1 p(2,2)=0.25 p(3,2)=0.1
p(1,3)=0.1 p(2,3)=0.1 p(3,3)=0.1
Compute the following probabilities:
P(X+Y>4)=
P(XY=3)=
P(XY>2)=
Answer by Boreal(15235) About Me  (Show Source):
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p(X+Y>4)=0.3, the (2, 3) (3, 2) and (3, 3)
P(XY=3)=0.2 using (3, 1) and (1, 3)
p(XY>2)=0.75, everything except (1, 2) (1, 1) and (2, 1)