SOLUTION: Let X represent the difference between the number of heads and the number of tails when a coin is tossed 41 times. Then P(X=11)=
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Question 1188499: Let X represent the difference between the number of heads and the number of tails when a coin is tossed 41 times. Then P(X=11)= Answer by ikleyn(52803) (Show Source):
You can put this solution on YOUR website! .
Let X represent the difference between the number of heads and the number of tails
when a coin is tossed 41 times. Then P(X=11)=
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It is very nice, slightly tangled probability problem.
I solved it (a TWIN version) once at this forum; see my lesson
- Challenging problems on Binomial distribution probability
(Problem 1) in this site. So, it is the second time I meet this problem at the forum . . .
Let H be the number of heads and T be the number of tails.
Then we have these two equations
H + T = 41
H - T = 11
We solve this system elementary, using elimination method, and we get H = = 26; T = 15.
Now the problem is: find the probability to get 26 heads tossing a coin 41 times.
The answer is P = = = 0.028845659 = 0.02885 (rounded).
