SOLUTION: This is a worksheet so i cant fill out the top. model each situation with a linear function and graph. is it reasonable to include negative numbers in the range? 1. a newly-s

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Question 118844: This is a worksheet so i cant fill out the top.
model each situation with a linear function and graph. is it reasonable to include negative numbers in the range?
1. a newly-started high school hopes to enroll 80 students in its first year and to increase enrollment by 40 students per eyar over the next five years.
5. temperature on the Fahrenheit scale is a linear function of temperature on the Celsius scale. Ten degrees Celsius equals 50 degrees Fahrenheit, and 25 degrees Celsius equals 77 degrees Fahrenheit.
(the temperature one really confuses me.)
Thanks for taking your time on reading this!

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
1. a newly-started high school hopes to enroll 80 students in its first year and to increase enrollment by 40 students per year over the next five years.
Let y = no. of students
Let x = no. of years
:
y = 40x + 80; on the initial opening of the school x=0
:
Plot it from x = 0 to x = 5:
x | y
-------
0 | 80
1 | 120
5 | 280
:
+graph%28+300%2C+200%2C+-2%2C+5%2C+-20%2C+300%2C+40x+%2B+80%29+
:
Negative values for x are not valid since the school did not exist before x=0
Same with negative values for y, negative students
(However, the existence of negative students is a debatable point)
:
:
5. temperature on the Fahrenheit scale is a linear function of temperature on the Celsius scale. Ten degrees Celsius equals 50 degrees Fahrenheit, and 25 degrees Celsius equals 77 degrees Fahrenheit.
:
Recall the formula for converting temp: F = 9%2F5C + 32
:
Let x = C, and y = F
Plotting table using the given values:
x | y
-------
10 | 50
25 | 77
:
+graph%28+300%2C+200%2C+-50%2C+100%2C+-50%2C+220%2C+%289%2F5%29x%2B32%29+
:
Negative values are certainly valid here, It's interesting that at -40 degrees
Celsius and Fahrenheit are equal
:
Did this help, any questions?