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| Question 1188408:  5 years ago, Fred was one-third Joe’s age. In 10 years, he will be two-thirds of Joe’s age. What is Fred’s age now?
 Found 2 solutions by  MathLover1, ikleyn:
 Answer by MathLover1(20850)
      (Show Source): Answer by ikleyn(52879)
      (Show Source): 
You can put this solution on YOUR website! . 5 years ago, Fred was one-third Joe’s age.
 In 10 years, he will be two-thirds of Joe’s age.
 What is Fred’s age now?
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 I read, understand and interpret the problem differently from the other tutor,
 so my solution and my answer are different.
 
 
 
 
Let Ferd's age be F and Jow's age be J.
First equation is 
    F - 5 =  I simplify it to
    3F - 15 = J - 5
    3F -  J = 10.      (1)
Second equation is
    F + 10 =  .
I simplify it to
    3F + 30 = 2J + 20
    3F - 2J = -10.     (2)
So, I have now this system of two equations in two unknowns
    3F -  J =  10      (1)
    3F - 2J = - 10     (2)
To solve it, apply the Eliminatiom method: from equation (1) subtract equation (2). You will get then
    -J - (-2J) = 10 - (-10)
       J       = 20.
Then from equation (1),  3F - 20 = 10,   3F = 10 + 20 = 30,  F = 30/3 = 10.
ANSWER.  Fred's age is 10 years;  Joe's age is 20 years.
CHECK.   5 years ago, they there 5 and 15 years old.
            
         In 10 years, their ages will be 20 and 30 years,
         so, the problem's conditions are satisfied.Solved.
 
 
 
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