SOLUTION: Alice had twice as much money as Peter. After Alice spent 1/6 of her money
and Peter spent
2/3 of his money, they had a total of $720 left.
(a) How much money did Alice and Pete
Algebra ->
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-> SOLUTION: Alice had twice as much money as Peter. After Alice spent 1/6 of her money
and Peter spent
2/3 of his money, they had a total of $720 left.
(a) How much money did Alice and Pete
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Question 1188380: Alice had twice as much money as Peter. After Alice spent 1/6 of her money
and Peter spent
2/3 of his money, they had a total of $720 left.
(a) How much money did Alice and Peter have altogether at first?
(b) Peter spent 3/4 of his remaining money on a bag. What fraction of his
original amount of money did he spend on the bag?
(Give your answer in its simplest form.)
You can put this solution on YOUR website! .
Alice had twice as much money as Peter. After Alice spent 1/6 of her money
and Peter spent
2/3 of his money, they had a total of $720 left.
(a) How much money did Alice and Peter have altogether at first?
(b) Peter spent 3/4 of his remaining money on a bag. What fraction of his
original amount of money did he spend on the bag?
(Give your answer in its simplest form.)
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I will solve part (a) only.
Let x be the amount Peter had at first, in dollars.
Then Alice had 2x dollars.
Write equation for the total remaining money after spending, as you read the problem
{{(5/6)(2x)}}} + = 720 dollars.
To solve, multiply both sides of the equation by 6 and simplify
10x + 2x = 6*720
12x = 6*720
x = = 6*60 = 360.
ANSWER. Peter had $360 at first; Alice had twice of it, i.e. $720 dollars.
Altogether, they had 360 + 720 = 1080 dollars, at first.
