.
Let u be the units digit.
Then the tens digit is u+3,
while the hundreds digit is 2*(u+3).
Notice that 2*(u+3) must be less or equal to 8, so
2(u+3) <= 8, so u+3 <= 8/2 = 4, which gives 0 <= u <= 1
Thus the formula for the value of the 3-digit number is
100*2*(u+3) + 10*(u+3) + u = 200(u+3) + 10*(u+3) + u,
where " u " is EITHER 0 or 1.
If u = 0, then the 3-digit number is 630;
if u = 1, then the 3-digit number is 841.
Solved and explained.