.
Let u be the units digit.
Then the tens digit is u+3,  
while the hundreds digit is 2*(u+3).
Notice that 2*(u+3) must be less or equal to 8, so
    2(u+3) <= 8,  so  u+3 <= 8/2 = 4,  which gives  0 <= u <= 1
Thus the formula for the value of the 3-digit number is
    100*2*(u+3) + 10*(u+3) + u = 200(u+3) + 10*(u+3) + u,
where  " u " is  EITHER  0  or  1.
If  u = 0,  then the 3-digit number is  630;
if  u = 1,  then the 3-digit number is  841.
Solved and explained.