SOLUTION: find the equation of the tangents and normal to curve x^2 = 3y, perpendicular to x - 2y + 7 = 0.

Algebra ->  Finance -> SOLUTION: find the equation of the tangents and normal to curve x^2 = 3y, perpendicular to x - 2y + 7 = 0.      Log On


   

Question 1188266: find the equation of the tangents and normal to curve x^2 = 3y, perpendicular to x - 2y + 7 = 0.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Too many similar problems.
Make an effort.
If you need help email via the TY note.