SOLUTION: Suppose the scores of students on an exam are Normally distributed with a mean of 436 and a standard deviation of 94. Then approximately 99.7% of the exam scores lie between the nu

Algebra ->  Probability-and-statistics -> SOLUTION: Suppose the scores of students on an exam are Normally distributed with a mean of 436 and a standard deviation of 94. Then approximately 99.7% of the exam scores lie between the nu      Log On


   

Question 1188236: Suppose the scores of students on an exam are Normally distributed with a mean of 436 and a standard deviation of 94. Then approximately 99.7% of the exam scores lie between the numbers and such that the mean is halfway between these two integers.
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
the mean is 436.
the standard deviation is 94.
to find the critical scores that have 99.7% of the area under the normal distribution curve between them, use this calculator.

https://davidmlane.com/hyperstat/z_table.html

the results of using the referenced calculator are shown below:



the scores that have 99.7% of the area under the normal distribution curve between them are 157.033 to 714.967.

the distance between them and the mean of 436 is plus or minus 278.967.

let me know if you have any questions.

theo