SOLUTION: Two consecutive odd number are chosen so that one third of the smaller exceed one seventh of the larger by 6.find the numbers.

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Question 1188233: Two consecutive odd number are chosen so that one third of the smaller exceed one seventh of the larger by 6.find the numbers.
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!


(1/3)n = (1/7)(n+2) + 6



n = 33, n+2 = 35



Check:

(1/3)n = (1/3)(33) = 11

and

(1/7)(n+2)+6 = (1/7)(35)+6 = 5+6 = 11  (ok)