SOLUTION: If r - (15 square root of r) + 50 = 0. Find the value of the cube root of (r + 2) assuming r is not equal to 100.

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Question 1188232: If r - (15 square root of r) + 50 = 0. Find the value of the cube root of (r + 2)
assuming r is not equal to 100.

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
If r - (15 square root of r) + 50 = 0. Find the value of the cube root of (r + 2)
assuming r is not equal to 100.
If r+-+15sqrt%28r%29+%2B+50+=+0. Find the value of root%283%2C%28r++%2B+2%29%29, assuming r%3C%3E100.

r+-+15sqrt%28r%29+%2B+50%22%22=%22%220

Let z%22%22=%22%22sqrt%28r%29, then z%5E2%22%22=%22%22r

z%5E2+-+15z+%2B+50%22%22=%22%220

z%5E2+-+15z+%2B+50%22%22=%22%220

%28z-5%29%28z-10%29%22%22=%22%220

z-5 = 0;  z-10 = 0
  z = 5;     z = 10

z%5E2%22%22=%22%22r},  z%5E2%22%22=%22%22r 

5%5E2%22%22=%22%22r,   10%5E2%22%22=%22%22r 

25%22%22=%22%22r,   100%22%22=%22%22r

Ignoring 100, r = 25.

root%283%2Cr++%2B+2%29
root%283%2C25++%2B+2%29
root%283%2C27%29
3

Edwin