SOLUTION: A reporter from the Centerville Star claims that the percentage of all Centerville residents who have criminal records is smaller than the percentage of all Edge City residents who

Algebra ->  Probability-and-statistics -> SOLUTION: A reporter from the Centerville Star claims that the percentage of all Centerville residents who have criminal records is smaller than the percentage of all Edge City residents who      Log On


   

Question 1188157: A reporter from the Centerville Star claims that the percentage of all Centerville residents who have criminal records is smaller than the percentage of all Edge City residents who have criminal records. To test this claim at the α=0.10 significance level, the reporter selects a random sample of 90 residents of Centerville and a random sample of 75 residents of Edge City. Eight of the people in the Centerville sample and nineteen of the people in the Edge City sample turn out to have criminal records.
Find the P-value for this hypothesis test.
Answer: P-value =
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
Ho: pC-PE>=0
Ha: pC-PE <0
alpha =0.10 p{reject Ho|Ho true}
test stat is a z, 1-way 2 sample proportion test
reject If Z <-1.28
calculation p1=0.0889; p2=0.253 p combined = 27/165=0.164
z=(0.0889-0.253)/ sqrt (0.164*0.836)((1/90)+(1/75))
=-0.164/sqrt(0.137*0.0244)
=-2.84
reject Ho and the proportion of those in Centerville is smaller than that those in Edge City.
p-value=0.0022