SOLUTION: Good evening ma'am or sir, would you please help me on how to solve these 4 equations : 1). 48ab^2c(4abc^0)^-2 2). 3x^0-n^-2 / -(3m-n) 3). (144*125 / 2^3*3^2)^-1 4). ab^-2 -

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Good evening ma'am or sir, would you please help me on how to solve these 4 equations : 1). 48ab^2c(4abc^0)^-2 2). 3x^0-n^-2 / -(3m-n) 3). (144*125 / 2^3*3^2)^-1 4). ab^-2 -      Log On


   



Question 118813: Good evening ma'am or sir, would you please help me on how to solve these 4 equations :
1). 48ab^2c(4abc^0)^-2
2). 3x^0-n^-2 / -(3m-n)
3). (144*125 / 2^3*3^2)^-1
4). ab^-2 - a^-2b
Thank you very much ma'am or sir for your generosity. :)

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
How to solve these 4 equations :
:
These are not equations (no equal sign), you can't solve them;.
You can factor/simplify them, which is probably what you want you to do:
:
1). 48ab%5E2c%284abc%5E0%29%5E-2
:
First of all any number, raised to ^0 = 1 so we can write:
48ab%5E2c%284ab%29%5E-2
:
A negative exponent can be made positive by using the reciprocal, so we have:
%2848ab%5E2c%29%2F%284ab%29%5E2
:
Square each term inside the brackets (denominator)
%2848ab%5E2c%29%2F%2816a%5E2b%5E2%29
:
CAncel and you have:
%283c%29%2Fa
:
:
2). %283x%5E0-n%5E-2%29%2F%28-%283m-n%29%29:
Follow the rules that we illustrated in the 1st one:
The reciprocal gets rid of the neg exponent, removing the bracket changes the signs
%283+-+%281%2Fn%5E2%29%29%2F%28-3m%2Bn%29;
:
Put the numerator into a single fraction form
%28%283n%5E2+-+1%29%2Fn%5E2%29%2F%28-3m%2Bn%29
:
Which is:
%28%283n%5E2+-+1%29%2Fn%5E2%29 * 1%2F%28-3m%2Bn%29 = %283n%5E2-1%29%2F%28n%5E2%28-3m%2Bn%29%29 = %283n%5E2-1%29%2F%28%28-3mn%5E2%2Bn%5E3%29%29
:
:
3). %28%28144%2A125%29%2F%282%5E3%2A3%5E2%29%29%5E-1
Do the math and invert to get rid of the ^-1:
%28%28144%2A125%29%2F%288%2A9%29%29%5E-1 = %2818000%2F72%29%5E-1 = 72%2F18000 = 1%2F250
:
:
4). %28ab%5E-2%29+-+%28a%5E-2b%29 = a%2Fb%5E2 - b%2Fa%5E2; using the reciprocals to get rid of the negative exponents
To put this over a single denominator:
%28a%5E3+-+b%5E3%29%2F%28a%5E2b%5E2%29