SOLUTION: Please help me. Thanks alot Elvin can buy 5 chocolate bars using 2/5 of his money. He can buy 3 chocolate bars and 18 sweets with the rest of his money. If he only buys sweets, h

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Question 1188021: Please help me. Thanks alot
Elvin can buy 5 chocolate bars using 2/5 of his money. He can buy 3 chocolate bars
and 18 sweets with the rest of his money. If he only buys sweets, how many
sweets can he buy with all his money?
Found 2 solutions by Theo, greenestamps:
Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website!
let x = all of his money.
let c = number of chocolate bars.
let s = number of sweets.

you have 2 equations that need to be solved simultaneously.

they are:

5c = 2/5 * x
3c + 18s = 3/5 * x

multiply both sides of each equation by 5 to get rid of the factions and get:

25c = 2x
15c + 90s = 3x

multiply both sides of the first equation by 3 and multiply both sides of he second equation by 5 to get:

75c = 6x
75c + 450s = 15x

subtract the first equation from the second to get:

450s = 9x

solve for x to get:

x = 50s

since x is all the money he has, then he can buy 50 sweets with all his money.

that's your solution.

let me know if you have any questions.

theo

Answer by greenestamps(13216) (Show Source):
You can put this solution on YOUR website!

There are many different ways to set up this problem for solving using formal algebra; the other tutor showed one. Here is another.

He can buy 5 chocolate bars with 2/5 of his money and 3 chocolate bars and 18 sweets with the remaining 3/5 of his money. So with all his money he can buy 8 chocolate bars and 18 sweets.

So the cost of 5 chocolate bars is 2/5 of the cost of 8 chocolate bars and 18 sweets:

The cost of each chocolate bar is 4 times the cost of each sweet.

He can buy 5 chocolate bars with 2/5 of his money; since he can buy 4 sweets for the price of one chocolate bar, he can buy 20 sweets with 2/5 of his money.

So the number of sweets he can buy with all his money is (5/2)*20 = 50.

ANSWER: 50 sweets