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Suppose an object moves along the y-axis so that its location is y = f(x) = x^2 + x at time x
(y is in meters and x is in seconds). Find the average velocity (the average rate of change of y
with respect to x) for x changing from 2 to 9 seconds.
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The position at x= 2 seconds is y = 2^2 + 2 = 4 + 2 = 6 meters at y-axis.
The position at x= 9 seconds is y = 9^2 + 9 = 81 + 9 = 90 meters at y-axis.
The displacement is 90-6 = 84 meters along y-axis in its positive direction.
The average velocity vector is 
= 
= 12 meters per second, directed along y-axis.
Solved and explained in all details; all necessary terms are pronounced.
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