SOLUTION: A person inflates a balloon. Assume that the balloon is spherical and that the person is blowing so that the volume increases at a rate of 1 L / s = 1000 cm3 / s (1 liter per secon

Algebra ->  Volume -> SOLUTION: A person inflates a balloon. Assume that the balloon is spherical and that the person is blowing so that the volume increases at a rate of 1 L / s = 1000 cm3 / s (1 liter per secon      Log On


   

Question 1187837: A person inflates a balloon. Assume that the balloon is spherical and that the person is blowing so that the volume increases at a rate of 1 L / s = 1000 cm3 / s (1 liter per second). a) Find an expression for the radius r of the balloon expressed using the volume V. b) Since the volume V increases, the radius r will also increase. Find an expression for the growth rate (dr/dt) to the radius using the expression you found in a). c) How fast does the radius increase when the volume is 3 L
Answer by Alan3354(69443) About Me  (Show Source):
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A person inflates a balloon. Assume that the balloon is spherical and that the person is blowing so that the volume increases at a rate of 1000 cm3/s
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a) Find an expression for the radius r of the balloon expressed using the volume V.
V+=+4pi%2Ar%5E3%2F3
r%5E3+=+3V%2F%284pi%29
r+=+root%283%2C%283V%2F%284pi%29%29%29
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b) Since the volume V increases, the radius r will also increase. Find an expression for the growth rate (dr/dt) to the radius using the expression you found in a)
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r+=+root%283%2C%283V%2F%284pi%29%29%29
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Battery is low, bbl.