SOLUTION: determine if each ordered pair is a solution of the system of in linear inequality {x+y>-2
{5x+y<2
1. (1,,-3)
2. (3,0)
3. (4,1)
4. (-10,4)
5. (5,6)
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-> SOLUTION: determine if each ordered pair is a solution of the system of in linear inequality {x+y>-2
{5x+y<2
1. (1,,-3)
2. (3,0)
3. (4,1)
4. (-10,4)
5. (5,6)
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Question 1187714: determine if each ordered pair is a solution of the system of in linear inequality {x+y>-2
{5x+y<2
1. (1,,-3)
2. (3,0)
3. (4,1)
4. (-10,4)
5. (5,6) Answer by Solver92311(821) (Show Source):
For each ordered pair, substitute the first number for in the inequality and the second number for . Do the indicated arithmetic. If the result is a true statement, the ordered pair is a solution to the linear inequality, otherwise, it is not a solution.
Example: . Hence (1,-3) is NOT a solution
John
My calculator said it, I believe it, that settles it
From
I > Ø
