Question 1187713: determine if each ordered pair is a solution of the system of in linear inequality {x+y>-2
{5x+y<2
1. (-1,,0)
2. (0-1)
3. (2,3)
4. (-3,-3)
5. (-4,4)
Answer by greenestamps(13200)   (Show Source):
You can put this solution on YOUR website!
Take each (x,y) pair and plug the numbers into both of the given inequalities. If the resulting inequalities are both true, then the pair is a solution; if either inequality is not true, the pair is not a solution.
You can do the work as easily as we can....
Here's one....
3. (2,3)
x+y > -2
2+3 > -2
5 > -2
TRUE
5x+y < 2
5(2)+3 < 2
10+3 < 2
13 < 2
FALSE
ANSWER: The second inequality is not true for (2,3), so (2,3) is NOT a solution to the system of inequalities
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