Question 1187686: Assume that a recent study revealed that 30% of youths in Luapula province are employed. A Sample of 8 youths in Luapula province is randomly selected, what is the probability that 3 or more youths are employed
Answer by ikleyn(52879)   (Show Source):
You can put this solution on YOUR website! .
Assume that a recent study revealed that 30% of youths in Luapula province are employed.
A Sample of 8 youths in Luapula province is randomly selected, what is the probability that 3 or more youths are employed?
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It is a binomial distribution problem.
The number of trials is 8; the number of successful trials is k >= 3 with the indexes k = 3, 4, 5, 6, 7, 8;
the probability of success for each single individual trial is p = 0.3.
Therefore, the formula to calculate the probability is
P(n=8; k>=3, p= 0.3) = 
To facilitate my calculations, I used online calculator at this site https://stattrek.com/online-calculator/binomial.aspx
It provides nice instructions and a convenient input and output for all relevant options/cases.
The resulting number is P = 0.44822619 = 0.4482 = 44.82% (rounded). ANSWER
Solved.
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If you want to see many similar (or different) solved problems, look into the lessons
- Simple and simplest probability problems on Binomial distribution
- Typical binomial distribution probability problems
- How to calculate Binomial probabilities with Technology (using MS Excel)
- Solving problems on Binomial distribution with Technology (using MS Excel)
- Solving problems on Binomial distribution with Technology (using online solver)
in this site.
After reading these lessons, you will be able to solve such problems on your own,
which is your PRIMARY MAJOR GOAL visiting this forum (I believe).
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