SOLUTION: What is the probability that an arrangement of the word BOOKKEEPER has 3 adjacent E’s in it? Example: BROKEEEKOP.

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Question 1187676: What is the probability that an arrangement of the word BOOKKEEPER has 3 adjacent E’s in it? Example: BROKEEEKOP.

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
Let "X" = "EEE"

The number of distinguishable arrangements of BOOKKXPR is 8!/(2!2!) = 10080.

The number of distinguishable arrangements of BOOKKEEPER is 10!/(2!2!3!) = 151200.

The probability is 10080 ways out of 151200 or 10080/151200 which reduces to 1/15.

Edwin