SOLUTION: What is the probability that at least 2 people in a group of 8 people have the same birthdate? (Assume every year has exactly 365 days - i.e., there is no Leap Day.)
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Question 1187672: What is the probability that at least 2 people in a group of 8 people have the same birthdate? (Assume every year has exactly 365 days - i.e., there is no Leap Day.)
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What is the probability that at least 2 people in a group of 8 people have the same birthdate?
(Assume every year has exactly 365 days - i.e., there is no Leap Day.)
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This probability is the COMPLEMENT to the probability that ALL 8 people have DIFFERENT birthdays.
The probability that 8 people have different birthdays is
Q = =
// (the product of 7 (seven) multipliers) = 0.925665...
Thus the probability under the problem's question is
P = 1 - Q = 1 - = 1 - 0.925665... = 0.0743 (rounded). ANSWER