SOLUTION: A box of 10 fuses has two defective fuses. In how many ways can one select three of these fuses and get (a) neither of the defective fuses, (b) one defective fuse, and (c) both of

Algebra ->  Probability-and-statistics -> SOLUTION: A box of 10 fuses has two defective fuses. In how many ways can one select three of these fuses and get (a) neither of the defective fuses, (b) one defective fuse, and (c) both of       Log On


   

Question 1187629: A box of 10 fuses has two defective fuses. In how many ways can one select three of these fuses and get (a) neither of the defective fuses, (b) one defective fuse, and (c) both of the defective fuses.
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.
A box of 10 fuses has two defective fuses. In how many ways can one select three of these fuses and get
(a) neither of the defective fuses,
(b) one defective fuse, and
(c) both of the defective fuses.
~~~~~~~~~~~~~~ 

(a)  In  C%5B8%5D%5E3 = %288%2A7%2A6%29%2F%281%2A2%2A3%29 = 8*7 = 56  different ways.             ANSWER


     In this case, the person must select triples from the set of 8 good fuses.



(b)  In  C%5B2%5D%5E1%2AC%5B8%5D%5E2 = 2%2A%28%288%2A7%29%2F%281%2A2%29%29 = 2*4*7 = 56  different ways.    ANSWER



(c)  In 8 different ways, by attaching one good fuse of 8 good fuses to 2 defective fuses.    ANSWER


Solved, answered and explained.