SOLUTION: the numerator of the fraction is one less than twice the denominator. If 3 is added to both numerator and denominator, the resulting fraction can be reduced to 3/2 what is the orig
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Question 1187499: the numerator of the fraction is one less than twice the denominator. If 3 is added to both numerator and denominator, the resulting fraction can be reduced to 3/2 what is the original fraction.
please help me :(
You can put this solution on YOUR website! let x = the denominator.
then 2x - 1 = the numerator.
your fraction is (2x - 1) / x.
add 3 to both numerator and denominator to get:
(2x + 2) / (x + 3) = 3/2
multiply both sides of the equation by (x + 3) to get:3x
2x + 2 = 3/2 * (x + 3)
multiply both sides of the equation by 2 to get:
4x + 4 = 3 * (x + 3)
simplify to get:
4x + 4 = 3x + 9
subtract 3x from both sides of the equation and subtract 4 from both sides of the equation to get:
x = 5.
that should be your solution.
confirm by replacing x in the original equation with 5 to get:
(2x - 1) / x becomes:
9 / 5
add 3 to both numerator and denominator to get:
12 / 8
simplify to get:
3/2.
x = 5 checks out ok.
your solution is that the original fraction is 9/5.
You can put this solution on YOUR website!
the numerator of the fraction is one less than twice the denominator. If 3 is added to both numerator and denominator, the resulting fraction can be reduced to 3/2 what is the original fraction.
please help me :(
Let denominator be D
Then numerator is: 2D - 1
We then get:
2(2D + 2) = 3(D + 3) ------ Cross-multiplying
4D + 4 = 3D + 9
4D - 3D = 9 - 4
Denominator, or D = 5
Numerator: 2D - 1 = 2(5) - 1 = 10 - 1 = 9
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