SOLUTION: 1. Find vectors ~v and ~w such that ~v is parallel to ~u = 2~ı − 3~j, ~w is perpendicular to ~u and ~v + ~w = 4~ı + 4~j. (The signs "~" are arrows that go above) 2. Find al

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: 1. Find vectors ~v and ~w such that ~v is parallel to ~u = 2~ı − 3~j, ~w is perpendicular to ~u and ~v + ~w = 4~ı + 4~j. (The signs "~" are arrows that go above) 2. Find al      Log On


   



Question 1187474: 1. Find vectors ~v and ~w such that ~v is parallel to ~u = 2~ı − 3~j, ~w is perpendicular to ~u and ~v + ~w = 4~ı + 4~j. (The signs "~" are arrows that go above)
2. Find all complex solutions of x^3 = 1 + i.

Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!

I will use bold v, u, and w to denote vectors, and
notation like u%5Bx%5D to denote components of a vector (here x component of vector u)
Hopefully it renders properly.

u = 2i - 3j (1)
From v || u: v = 2ci-3cj (2)
where c is some scaler value.

From w perpendicular to u: wu = 0
which translates to
2w%5Bx%5D - 3w%5By%5D = 0 (3)
We also want: w + v = 4i + 4j (4)
(3) ==> +w%5By%5D+=+%282%2F3%29w%5Bx%5D+
Now we can write, using (3) and (4):
(5) 2c + w%5Bx%5D = 4
{6) -3c + %282%2F3%29w%5Bx%5D = 4
Solving this for c gives c=-4%2F13 which tells us via (2)
that v = (-8/13)i + (12/13)j

Now you can use (5) and (6) to solve for w%5Bx%5D or plug c into
(4) and solve for w%5Bx%5D and w%5By%5D (I did it the latter way):
w = (60/13)i + (40/13)j


Check:
I checked everything but you should do so as an exercise.
1. Check that w + v = 4i + 4j
2. Check that wu = 0 (w%5Bx%5Du%5Bx%5D+%2B+w%5By%5Du%5By%5D+=+0+)
3. Check that |vu| = |v||u|