SOLUTION: Find the equation of a parabola with vertex on the line y = x + 2, axis parallel to Oy, latus rectum 6 and passing through ( -3, -1).

Algebra ->  Finance -> SOLUTION: Find the equation of a parabola with vertex on the line y = x + 2, axis parallel to Oy, latus rectum 6 and passing through ( -3, -1).      Log On


   

Question 1187363: Find the equation of a parabola with vertex on the line y = x + 2, axis parallel to Oy, latus rectum 6 and passing through ( -3, -1).
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

There is more than one solution.
Note that (-3,-1) is on the line y=x%2B2, so the vertex can be (h,k)=(-3,-1).
It doesn’t have to be there, but that is an easy solution.
Length of latus rectum is 6, so the leading coefficient is a=±%281%2F6%29
using vertex form:

or
y+=+-%281%2F6%29%28x%2B3%29%5E2-1

see the graph:
first solution: y+=+%281%2F6%29%28x%2B3%29%5E2-1+



second solution: y+=+-%281%2F6%29%28x%2B3%29%5E2-1+