SOLUTION: 2. Find the equation of the parabola with vertex at (5, 4) and focus (5, 2).

Algebra ->  Finance -> SOLUTION: 2. Find the equation of the parabola with vertex at (5, 4) and focus (5, 2).      Log On


   



Question 1187357: 2. Find the equation of the parabola with vertex at (5, 4) and focus (5, 2).
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Use Definition of Parabola and the Distance Formula, and then simplify and put into whatever form of equation you need. According to your given description, directrix is y=6.

If start with %28x-5%29%5E2%2B%28y-2%29%5E2=%28x-x%29%5E2%2B%28y-6%29%5E2
and go through algebraic steps
you should find
highlight%28%28x-5%29%5E2=-8%28y-4%29%29.

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


You are given the vertex (5,4); and given the focus (5,2), you know the parabola opens downward.

The vertex form of the equation I prefer to use is

y-k+=+%281%2F%284p%29%29%28x-h%29%5E2

where (h,k) is the vertex and p is the directed distance (i.e., can be negative) from the vertex to the focus.

You are given (h,k) = (5,4); and the given vertex and focus tell us p = -2. So 4p = -8, and the equation is

y-4+=+-%281%2F8%29%28x-5%29%5E2