SOLUTION: Admission prices in the bunawan variety shows where 20 pesos and fifty pesos the total cash in one of the ticket booth was 9550 tickets were sold to 320 people how many of each kin
Question 1187198: Admission prices in the bunawan variety shows where 20 pesos and fifty pesos the total cash in one of the ticket booth was 9550 tickets were sold to 320 people how many of each kind of tickets were sold
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Admission prices in the bunawan variety shows where 20 pesos and fifty pesos
the total cash in one of the ticket booth was 9550 tickets were sold to 320 people
how many of each kind of tickets were sold
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It looks like a standard ticket problem.
You can start from the standard form equations
x + y = 320 (1)
20x + 50y = 9550 (2)
where x is the number of the 20-pesos tickets; y is the number of the 50-pesos tickets.
Then you express x = 320-y from the first equation and substitute it into the second equation
20(320-y) + 50y = 9550 pesos. (3)
Alternatively, you can start directly from equation (3) - it is up to you.
From equation (3),
y = = 105.
So, there are 105 50-peso tickets, and the rest (320-105) = 215 tickets are for 20 pesos. ANSWERCHECK. 50*105 + 20*215 = 9550 pesos, the total money. ! Correct !
