SOLUTION: If Keegan does a job in 9 hours and with the help of Caitlyn they can do it together in 6 hours, how long would it take Caitlyn to do it alone?

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Question 1187185: If Keegan does a job in 9 hours and with the help of Caitlyn they can do it together in 6 hours, how long would it take Caitlyn to do it alone?
Found 3 solutions by Alan3354, josgarithmetic, ikleyn:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Depends on the job, right?
What are they wearing?

Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
1%2F9%2B1%2Fc=1%2F6 using c for the time for Caitlyn to do the job alone.
SOLVE FOR c.

Answer by ikleyn(52878) About Me  (Show Source):
You can put this solution on YOUR website!
.

Working with Caitlyn 6 hours, Keegan, OBVIOUSLY, makes  6%2F9 = 2%2F3  of the job.


It means, that during 6 hours Caitlyn makes remaining  1%2F3  of the job.


Then it is clear that Caitlyn needs 6*3 = 18 hours to make the entire job alone.

Solved.