SOLUTION: A car traveling at 45 mph overtakes a cyclist who, riding at 20 mph, had a 2-hour head start. How far from the starting point does the car overtake the cyclist?
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Question 1187050: A car traveling at 45 mph overtakes a cyclist who, riding at 20 mph, had a 2-hour head start. How far from the starting point does the car overtake the cyclist?
Let t be the travel time of the car (in hours);
then the travel time of the cyclist is (t+2) hours.
The distance equation is
45*t = 20*(t+2).
Simplify and find t
45t = 20t + 40
45t - 20t = 40
25t = 40
t = = hours = 1 hours = 1 hour and 36 minutes = 1.6 hours.
The distance from the start to the catching point is 45*1.6 = 72 miles. ANSWER
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A car traveling at 45 mph overtakes a cyclist who, riding at 20 mph, had a 2-hour head start. How far from the starting point does the car overtake the cyclist?
Let distance from starting point be D
Then time taken for the car and bike to get to the meeting point = , respectively
With the car taking 2 hours less to get to meeting point, we get the following TIME equation:
4D = 9D - 360 ------ Multiplying by LCD, 180
4D - 9D = - 360
- 5D = - 360
Distance from the starting point, where the bike was overtaken, or