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log2(x) + log2(x+1) = 1
~~~~~~~~~~~~~
I assume that the logarithms are base 2.
From
log2(x) + log2(x+1) = 1
we have, using the property of logarithms,
x*(x+1) = 2
Making FOIL, you get
x^2 + x - 2 = 0.
Factor
(x+2)*(x-1) = 0.
We deny the negative root x= -2, since it does not work under logarithm.
The only remaining solution is x= 1. ANSWER
Solved.
