SOLUTION: 1. A delivery boy collected P5.35, part in 5¢ coins(nickels) and part in 10¢ coins (dimes). If the number of 5¢ coins(nickels) were 7 more than one-half the number of 10¢ c

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Question 1186980: 1. A delivery boy collected P5.35, part in 5¢ coins(nickels) and part in 10¢ coins
(dimes). If the number of 5¢ coins(nickels) were 7 more than one-half the
number of 10¢ coins (dimes), how many 5¢ coins(nickels) were there?
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
nickels count d%2F2%2B7, d for the count of dimes

if n=d/2+7, then 2n=d%2B14, d=2n-14.

5n%2B10%282n-14%29=535
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n%2B2%282n-14%29=107
n%2B4n-28=107
5n=107%2B28
5n=135
highlight%28n=27%29