Question 1186950: The mean height of an adult giraffe is 17 feet. Suppose that the distribution is normally distributed with standard deviation 0.9 feet. Let X be the height of a randomly selected adult giraffe. Round all answers to 4 decimal places where possible.
c. What is the Z-score for a giraffe that is 18.5 foot tall?
d. What is the probability that a randomly selected giraffe will be shorter than 17.5 feet tall?
e. What is the probability that a randomly selected giraffe will be between 16.7 and 17.2 feet tall?
f. The 70th percentile for the height of giraffes is
ft.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! z=(x-mean)/sd
c. 1.5/0.9=-score=1.6667
d. z<0.5/0.9 which is 0.7107
e. can do a z for <16.7 (-0.33) and one for <17.2 (+0.222) and subtract first probability from second (0.2183). OR, calculator (normalcdf(16.7,17.2,17,0.9)=0.2185. Where you round for z makes a difference in the fourth place.
f. invnorm(0.7,0,1)=0.5244
z=(x-mean)/sd
x-mean=0.4720
answer is 17.4720 feet tall
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